Evaluate the piecewise function below for f(0): f(x) = { 5 if x < 0x + 3 if 0 < = x < = 42x - 1 if x > 4write answer as a single number

Evaluate f(0)

We have 3 different function inside piecewise function

f(x) = 5 if x < 0

f(x)= x + 3 if 0 <= x <= 4

f(x) = 2x - 1 if x > 4

f(0) means we need to find f(x) when x=0

Now we check all the inequalities that satisfies x=0

0 <= x <= 4  means x = 0  to 4 but 4 is not included

x=0 satisfies the inequality  0 <= x <= 4

So we use f(x)= x + 3  to find f(0)

Replace x  with 0

f(x)= x + 3

f(0)= 0 + 3 = 3

f(0) = 3

Explanation:

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