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ajernandes01
04.09.2020 •
Mathematics
Explain how to factorise i,j and n
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Ответ:
I).
(x+5)^2 - 16 = 0
It’s in a form of: a^2 - b^2 = (a-b)(a+b)
(x + 5)^2 - 4^2 = 0
(x + 5 - 4)(x + 5 + 4) = 0
(x + 1)(x + 9) = 0
J.
(x - 4)^2 - 9 = 0
Same form: a^2 - b^2 = (a-b)(a+b)
(x - 4)^2 - 3^2 = 0
(x - 4 - 3)(x - 4 + 3) = 0
(x - 7)(x - 1) = 0
n).
(2y + 7)^2 - y^2 = 0
(2y + 7 - y)(2y + 7 + y) = 0
(y + 7)(3y + 7) = 0
Ответ:
see explanation
Step-by-step explanation:
A difference of squares is factored in general as
a² - b² = (a - b)(a + b)
(i)
(x + 5)² - 16 ← is a difference of squares, that is
(x + 5)² - 4²
= (x + 5 - 4)(x + 5 + 4)
= (x + 1)(x + 9)
(j)
(x - 4)² - 9 ← is a difference of squares, that is
(x - 4)² - 3²
= (x - 4 - 3)(x - 4 + 3)
= (x - 7)(x - 1)
(n)
(2y + 7)² - y² ← is a difference of squares
= (2y + 7 - y)(2y + 7 + y)
=(y + 7)(3y + 7)
Ответ:
but it is
81X^28-n
Step-by-step explanation: