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KP1998
08.07.2019 •
Mathematics
Express the ratio 3 2/3 7 1/3 in its simplest form
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Ответ:
The ratio is![\frac{3\frac{2}{3} }{7\frac{1}{3} }](/tpl/images/0064/7778/e967d.png)
The fraction
in improper fraction form is ![\frac{11}{3}](/tpl/images/0064/7778/fb14b.png)
Similarly,
in improper fraction form is ![\frac{22}{3}](/tpl/images/0064/7778/5a9ac.png)
Therefore, the ratio is![\frac{\frac{11}{3} }{\frac{22}{3} }](/tpl/images/0064/7778/f69dd.png)
Therefore, the ratio in the simplest form is![\frac{1}{2}](/tpl/images/0064/7778/9cdae.png)
Ответ:
remember
the deritivive of f(x)/g(x)=(f'(x)g(x)-g'(x)f(x))/(g(x)^2)
so
2x+2y(dy/dx)=0
minus 2x
2y(dy/dx)=-2x
divide both sides by 2y
dy/dx=-x/y
take derivitve again
(-x'y-y'x)/(y^2)
remember, y'=dy/dx=-x/y
(-y-(-x/y)x)/(y^2)
at (4,3)
at x=4 and y=3
(-3-(-4/3)4)/(3^2)=
(-3+16/3)/9=
(-9/3+16/3)/9=
(7/3)/9=
7/27
the value is 7/27
it is concave up at that point btw