Express x^2-5x+8 in the form (x-a)^2+b

x^2 - 5x + 8 = (x - 5/2)^2 + 7/4

Step-by-step explanation:

(x - a)^2 + b = x^2 - 2ax + a^2 + b

equate to your quadratic :

x^2 - 5x + 8 = x^2 - 2ax + (a^2 + b)

equating coefficients (ignoring x^2 as the coefficient is 1 for both)

for x :

-5 = -2a --> a = 5/2

for x^(0) : 8 = a^2 + b , note a = 5/2

thus,

8 = (5/2)^2 + b

8 = 25/4 + b

b = 8 - 25/4 = 32/4 - 25/4 = (32 - 25)/4 = 7/4

hence a = 5/2 , b = 7/4

thus,

x^2 - 5x + 8 = (x - 5/2)^2 + 7/4

I'm not sure if I'm correct but I think it's F=5

Step-by-step explanation:

6 times 5 = 30