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hi105
20.09.2019 •
Mathematics
F(x) = square root of quantity three x plus seven. , g(x) = square root of quantity three x minus seven.
find (f + g)(x).
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Ответ:
g(x) = sqrt(3x-7)
(f+g)(x) = sqrt(3x+7) +sqrt(3x-7)
Ответ:
Step-by-step explanation:
we need to find (f+g)(x)
(f+g)(x)= f(x) + g(x)
replace f(x) and g(x) expressions
(f+g)(x)= f(x) + g(x)=![\sqrt{3x+7} + \sqrt{3x-7}](/tpl/images/0247/2947/2a595.png)
both square root have different terms inside the root
so we cannot add square root terms.
Ответ:
3.75
Step-by-step explanation: (Might need calculator)
You said "The sum of four times a number and negative three us twelve. What is the number? " which means 4n+(-3)=12.
4n is 4*n, to let you know.
To make it easier, you can turn 4n+(-3)=12 into 4n-3=12. From there you can complete the process:
4n-3=12
Add 3 to both sides (12+3=15) (-3+3=0, they cancel out)
4n=15
Divide both sides by 4 (15/4=3.75) (4/4=1, they cancel out)
You get=
n=3.75 or 3 3/4
Lets double check:
4n-3=12
4(3.75)-3=12
15-3=12
12=12
True. Hope this helps!