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cedarclark9534
22.06.2019 •
Mathematics
Factor the polynomial: -2x^3 - 4x^2 - 6x a. 2x(x^2 + 2x + 3) b. -2x(x^2 + 2x +3) c. -2x(-x^2 - 4x - 6) d. -2x(-x^2 - 2x - 3)
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Ответ:
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-2x3-4x2-6x
Final result :
-2x • (x2 + 2x + 3)
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((0 - (2 • (x3))) - 22x2) - 6x
Step 2 :
Equation at the end of step 2 :
((0 - 2x3) - 22x2) - 6x
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
-2x3 - 4x2 - 6x = -2x • (x2 + 2x + 3)
Trying to factor by splitting the middle term
4.2 Factoring x2 + 2x + 3
The first term is, x2 its coefficient is 1 .
The middle term is, +2x its coefficient is 2 .
The last term, "the constant", is +3
Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3
Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is 2 .
-3 + -1 = -4
-1 + -3 = -4
1 + 3 = 4
3 + 1 = 4
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
-2x • (x2 + 2x + 3)
Step-by-step explanation:
Ответ: