Mathematics: Factor (x-1)^3 (4x-9) - (16x+9) (x+1)^2 ? explain steps, i m stuck !

Factor (x-1)^3 (4x-9) - (16x+9) (x+1)^2 ? explain

joelpimentel

12.03.2022

(x-1)^3 (4x-9) - (16x+9) (x+1)^2

= (x^3-3x^2+3x-1) (4x-9) - (16x+9) (x^2+2x+1)

= (4x^4-12x^3+12x^2-4x-9x^3-27x^2-27x+9)-(16x^3+32x^2+16x+9x^2+18x+9)

= (4x^4-21x^3+39x^2-31x+9)-16x^3-32x^2-16x-9x^2-18x-9

= 4x^4-21x^3+39x^2-31x+9-16x^3-32x^2-16x-9x^2-18x-9

= 4x^4-37x^3-2x^2-65x

= x(4x^3-37x^2-2x-65)

hence final factor is x(4x^3-37x^2-2x-65)

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clairajogriggsk

15.06.2021

-3-(-5)=-8

Step-by-step explanation:

-3 minus another negative like -5 will equal a bigger negative so take 5 + 3 and you would get 8 but since it is a negative you would get a -8

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