Mathematics: Factorise the given expressions : a) (6p2 – 36p + 30) b) (256 − 64y + 4y2 )

Factorise the given expressions : a) (6p2 – 36p - id6236310602541, joannegrace4898

Cedars6976

17.03.2022

a) Factorizing 6p^2 - 36p + 30 we get 6(p-5)(p-1)

b) Factorizing 4y^2-64y+256 we get 4(y-8)(y-8)

Step-by-step explanation:

Factorise the given expressions :

a) 6p^2 - 36p + 30

First we take 6 common:

$6p^2-36p+30\\=6(p^2-6p+5)\\=6(p^2-5p-p+5)\\=6(p(-5)-1(p-5))\\=6(p-5)(p-1)\\$

So, factorizing 6p^2 - 36p + 30 we get 6(p-5)(p-1)

b) 256 -64y + 4y^2

Rearranging terms:

4y^2-64y+256

Taking 4 common

$4(y^2-16y+64)\\4(y^2-8y-8y+64)\\4(y(y-8)-8(y-8))\\4(y-8)(y-8)$

So, factorizing 4y^2-64y+256 we get 4(y-8)(y-8)

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trevorhenyan51

07.07.2022

N(t)=52(9/7)^t

Step-by-step explanation:

hope it's helpful..

have a great day

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