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rosehayden21
05.10.2019 •
Mathematics
Fernando has some nickels, dimes, and quarters that are worth a total of $3.25. he has twice as many dimes as nickels. he has 3 more quarters than nickels.
how many nickels, dimes, and quarters does fernando have?
let x represent the number of nickels.
write and solve a linear equation in one variable.
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Ответ:
Number of nickels = 5
Number of dimes = 10
Number of quarters = 8
Step-by-step explanation:
Fernando has a total of nickels + dimes + quarters = 3.25$
Let the number of nickels = x
Then x(.05) + dimes(.10) + quarters(0.25) = 3.25(1)
He has twice as many dimes as nickels
dimes = 2×nickels
dimes = 2x(2)
He has 3 more quarters than nickels
quarters = nickels +3
quarters = x +3(3)
From equations 1, 2, and 3.
x(.05) + 2x(.10) + (x + 3)(.25) = 3.25
.05x + 0.2x + 0.25x + .75 = 3.25
5x + 20x + 25x + 75 = 325
50x = 325 - 75
50x = 250
x = 5
Therefore the number of nickels are 5
from equation 2 number of dimes are 10
and from equation 3 number of quarters are 8.
Ответ: