Fifteen is six more than a number. Two-fifths of a number is twenty.
Thirty is seven less than twice a number.

idrk what you're asking here but I tried to solve it. fifteen is six more than a number=9

2/5 of a number is 20= 50(?)

thirty is seven less than twice a number= 74

Step-by-step explanation:

for the first one I subtracted 6 from 15 and got 9.

for the second one I was a little confused but I thought that because 2/5 was 20 than 1/5 would be 10. so I just counted 10,20,30,40,50. then I put 50/5 and simplified it to get 10/1 (further simplified as 10).

for the third one I wrote out the problem:

x2

-7

30

and I did everything back wards.

30+7= 37

37×2=74

I hope this helps, it was a bit confusing

DE = 3 units

Step-by-step explanation:

The image is attached.

There are 2 secant lines in the circle. We can use secant theorem to solve this easily.

It states that "if 2 secants are drawn to a circle from an outside point, then product of 1 secant and its "outside" part is equal to product of other secant and its "outside" part.

From the figure, we can say:

AX * BX = EX * DX

We let the length to find , DE, be "x".

Thus, we can write:

Now, we solve this for x:

Thus,

DE = 3 units