Figure A is the pre-image. If figure A is rotated 90° clockwise or 270° counterclockwise using center (0,0), what would be the coordinates of S' in the
image?

Round off the decimal to the nearest tenths.

0.82

The answer is 0.80

Step-by-step explanation:

When I learned rounding, we would round to the place value behind it then if its less than 5 than my answer would be what its rounded to. If I round 92 to the nearest tenth, it would be 90 because 2 is not greater than 5 so it would round to 90 because its the nearest tenth. If it was 95 it would be rounded to 100, any number that is 5 to 9 would be rounded to the greater tenth closer to it. So 0.82 is less than 5 nor 5 so it would round up to 0.80