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nathanphelps2468
01.10.2019 •
Mathematics
Fill in the missing terms of the following sequence
-3, _, -13
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Ответ:
12,7,2,-3,-8,-13
Step-by-step explanation:
Changes by -5
Ответ:
Ответ:
Step-by-step explanation:![\displaystyle\ \bigg{2^x-3(2^{x+\frac{1}{2} }})+2^2=0 \qquad ; \ \ \boxed{t=2^x} \\\\t-3t\sqrt{2} +4=0 \\\\ t(1-3\sqrt{2} )=-4 \\\\ t=\frac{4}{3\sqrt{2} -1} \cdot \frac{3\sqrt{2}+1 }{3\sqrt{2}+1 } =\frac{12\sqrt{2}+4}{17} \\\\\\2^x=\frac{12\sqrt{2}+4}{17} \\\\x=log_2 \ \ \frac{12\sqrt{2}+4}{17}](/tpl/images/1391/5469/05da7.png)