Find 3 consecutive integers such that the sum of smallest and five times the largest is 196

Let x is the smallest integer
x+1 is the middle integer
x+2 is the largest integer

sum of smallest and five times the largest is 196
x +5(x + 2) = 196
x + 5x + 10= 196
6x + 10 = 196
6x = 186
x = 186/6
x = 31

x+1 =31+1 = 32
x+2 =31+2 =33

proof:

sum of smallest and five times the largest is 196

x +5(x + 2) = 196
31+5(31+2) = 196
31+5(33)=196
31+165=196
196=196 ...> true

3 consecutive integers are 31,32,33

(L + 10)/(L + 16) = 0.8

Step-by-step explanation:

She needs to answer L more questions to get a grade of 80%.

When she answers L more questions correctly, she will have answered L + 10 questions correctly.

The total number of questions will be L + 16.

L + 10 must be 80% of L + 16

(L + 10)/(L + 16) = 0.8