cylertroutner
03.11.2020 •
Mathematics
Find a numerical value of one trigonometric function of x if 
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Ответ:
(tan²(x) - sin²(x)) / sin²(x) = 5
tan²(x) / sin²(x) - sin²(x) / sin²(x) = 5
(sin²(x) / cos²(x)) / sin²(x) - sin²(x) / sin²(x) = 5
If sin(x) ≠ 0, then the equation reduces to
1 / cos²(x) - 1 = 5
sec²(x) = 6
sec(x) = ± √6
x = arcsec(√6) + 2nπ or x = arcsec(-√6) + 2nπ
(where n is any integer)
Ответ: