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nakeytrag
28.12.2019 •
Mathematics
Find a power series for f(x)=xln(1+x). \[f(x)=xln(1+x)\]. \[\frac{d}{dx}xln(1+x)\]. \[=\frac{x}{x+1}+ln(x+1)\]. \[=\sum_{n=0}^{\infty}(-1)^nx^n+\frac{d}{dx}ln(x+1)\]. \[\sum_{n=0}^{\infty}(-1)^nx^n+\sum_{n=0}^{\infty}(-1)^n\frac{x^{n+1}}{n+1}\]
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Ответ:
Ответ:
91,542
Step-by-step explanation:
I would assume that all other parts of the question are irrelevant and what you really want solved is:
2+897+90643
IN that case, using addition we can achieve 91,542 as our answer.
Thus, the answer is 91,542.