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knighiv
03.11.2019 •
Mathematics
Find all real and complex zeros of p(x)=x^3-x^2-4x-6
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Ответ:
x = 3 , -1 +
, -1 - ![\sqrt{-1}](/tpl/images/0357/3424/d2426.png)
Step-by-step explanation:
⇒![p(x)=x^{3} -x^{2} -4x-6](/tpl/images/0357/3424/d3327.png)
⇒![p(x)=(x-3)(x^{2} +2x+2)](/tpl/images/0357/3424/c2050.png)
now, for zeros of
,
⇒ x =
± ![\frac{\sqrt{b^{2}-4ac } }{2a}](/tpl/images/0357/3424/d1f2e.png)
⇒ x =
± ![\frac{\sqrt{2^{2}-4(2) } }{2}](/tpl/images/0357/3424/d10a1.png)
⇒ x = -1 ±![\sqrt{-1}](/tpl/images/0357/3424/d2426.png)
hence, all the roots are,
x = 3, -1 +
, -1 - ![\sqrt{-1}](/tpl/images/0357/3424/d2426.png)
Ответ:
The answer on E2020 is C.) 14