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14.10.2019 •
Mathematics
Find all solutions in the interval [0, 2π).
sin^2 x + sin x = 0
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Ответ:
sin x( sin x + 1) = 0
sin x = 0 , or sinx + 1 = 0 giving sin x = -1
when sin x = 0 x = 0 , pi
when sin x = -1, x = pi + pi/2 = 3pi/2
solutions in given interval are 0,pi and 3pi/2
Ответ:
x+19= 2x-x+19
Step-by-step explanation: