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clairajogriggsk
08.04.2020 •
Mathematics
Find all the solutions of sin x + cos x = 1 in the interval [0, 2pie).
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Ответ:
X = 0, π/2 in the interval [0, 2pi).
Step-by-step explanation:
Use the auxiliary angle method:
R sin(x + a) = Rsin x cos a + Rcos x sin a = 1
sin x + cos x = 1
Comparing coefficients:
R cos a = 1 and R sin a = 1, so
tan a = R sin a / R cos a = 1
So a = π/4 radians.
Also R^2(sin^2 a + cos^2 a) = 1^2 + 1^2 = 2
Therefore R = √2.
So √2 sin (x +π/4 = 1
sin x + π/4 = 1/√2
x + π/4 = π/4
x = 0 radians
Also
x = 0 + π/2 = π/2.
Ответ: