Mathematics: Find all the values of k so that the given points are 29 square units apart. (-5, 5) and (k,0).

Find all the values of k so that the given points

Ответ:

taylenlane4213

07.01.2022

Distance formula between 2 points (x1,y1) and (x2,y2)

D= $\sqrt{(x1-x2)^{2}+(y1-y2)^{2}}$

D=29 and one point is (-5,5) and the other is (k,0)
sub

29= $\sqrt{(-5-k)^{2}+(5-0)^{2}}$
29= $\sqrt{(-5-k)^{2}+(5)^{2}}$
square both sides
841= $(-5-k)^{2}+(5)^{2}$
841= $(-5-k)^{2}+25$
minus 25 both sides
816= $(-5-k)^{2}$
square root both sides don't forget positive and negative roots
+/-4√51=-5-k
add 5 to both sides
5+/-4√51=-k
times -1 both sides
-5+/-4√51=k

the possible values for k are
k=-5+4√51 or k=-5-4√51

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Ответ:

jaydenromero31

19.12.2022

Mathematics

it would also be 3/4x (in terms of y=mx+c)

Step-by-step explanation:

parallel lines have the same slope/gradient

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Find all the values of k so that the given points are 29 square units apart. (-5, 5) and (k,0).

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