Mathematics: Find all the zeros of the equation -3x^4+27^2+1200=0 if you could show yourworkthat would be great : 3

The amount of money A pays is Step-by-step explanation:Letx----- amount of money A paysy----- amount of money B payswe know that ------ equation Aso ------ equation Bsubstitute equation B in equation A and solve for x...

Find all the zeros of the equation -3x^4+27^2+1200=0 - id342721200271617, helloitschump0vfdz

Ответ:

tatielder4896

10.03.2022

Mathematics

Divide both sides by -3, and replace x^2 with . Then

$-3x^4+27x^2+1200=0\iff y^2-9y-400=0$

Factorize the quadratic in to get

$y^2-9y-400=(y+16)(y-25)=0\implies y=-16,y=25$

which in turn means

x^2=-16,x^2=25

But $x^2\ge0$ for all real , so we can ignore the first solution. This leaves us with

$x^2=25\implies x=\pm\sqrt{25}=\pm5$

If we allow for any complex solution, then we can continue with the solution we ignored:

$x^2=-16\implies x=\pm\sqrt{-16}=\pm i\sqrt{16}=\pm4i$

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Ответ:

andrewgainey1986

17.07.2022

Mathematics

The amount of money A pays is $\$51$

Step-by-step explanation:

Let

x-----> amount of money A pays

y-----> amount of money B pays

we know that

x+y=85 ------> equation A

$\frac{x}{y}=\frac{3}{2}$

$y=\frac{2}{3}x$ ------> equation B

substitute equation B in equation A and solve for x

$x+(\frac{2}{3}x)=85$

$\frac{5}{3}x=85$

$x=85*3/5=\$51$

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Find all the zeros of the equation -3x^4+27^2+1200=0 if you could show yourworkthat would be great : 3

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