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StateChamps
20.09.2020 •
Mathematics
Find all values of k such that the graph of the inequality (x-2)(x-5)(x-k) >= 0 consists of a single interval on the number line.
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Ответ:
(x - 2)(x - 5)(x - k) >= 0
Let's set each term equal to 0
x - 2= 0
Add 2 to both sides
x = 2.
x - 5 = 0
Add 5 to both sides
x = 5
x - k = 0
Add k to both sides
x = k
Since x = 2 and 5, k = 2, 5
Let's plug our numbers into the inequality.
(2 - 2)(2 - 5)(2 - 2) >= 0
(0)(-3)(0) >= 0
0>=0
(5 - 2)(5 - 5)(5 - 5) >= 0
(3)(0)(0) >= 0
0 >= 0
This proves that 2 and 5 are equal to k
Ответ:
22 1/12
Step-by-step explanation:
48*22=1056
1060-1056=4
= 22 4/48
= 22 1/12
So the answer is 22 1/12,
Hope this helps!