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qwemnb7401
19.09.2021 •
Mathematics
Find an equation for line perpendicular to 2x+6y=18 and goes through the point (8,-1)
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Ответ:
y = 3x - 25
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
2x + 6y = 18 ( subtract 2x from both sides )
6y = - 2x + 18 ( divide terms by 6 )
y = -
x + 3 ← in slope- intercept form
with slope m = -![\frac{1}{3}](/tpl/images/2469/4370/5506e.png)
Given a line with slope m then the slope of a line perpendicular to it is
y = 3x + c ← is the partial equation
To find c substitute (8, - 1 ) into the partial equation
- 1 = 24 + c ⇒ c = - 1 - 24 = - 25
y = 3x - 25 ← equation of perpendicular line
Ответ:
168
Step-by-step explanation:
the area of this shape is determined by base and height so how it work is...
a=b*h
the base here is 14 the height is 12 so what is 12 times 14?
168