Find an equation for the line perpendicular to the line -8x+4=3 having the same y-intercept as -7x+3y=-8.

3X-4Y=12
-4Y=-3X+12
Y=-3X/-4+12/-4
Y=3X/4-3 THUS THE SLOPE OF THIS LINE IS 3/4. 
THUS A PERPENDICULAR LINE HAS A SLOPE THAT IS A NEGATIVE RECIPRICAL OF 3/4 WHICH IS -4/3
NOW FIND THE X INTERCEPT FOR 
4X-13=3Y
3Y=4X-13

Y=4X/3-13/3 TO FIND THE X INTERCEPT OF THIS LINE WE SET Y=0 THUS:
0=4X/3-13/3
4X/3=13/3
X=13/3*3/4
X=13/4 NOW WE NEED TO FIND THE Y INTERCEPT (b)
0=-4/3*13/4+b
0=-13/3+b
b=13/3 THUS THE EQUATION IS
Y=-4X/3+13/3

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