Find an equation for the line that is parallel to the line 3x+4y=11, and contains the point (8,0).

Quick approach:  Write out 3x+4y=11 and then replace the constant (11) with C:

3x+4y=C.  Next, substitute 8 for x and 0 for y, obtaining:

3(8) + 4(0) = C.  Then C = 24, and the desired equation is   3x+4y=24.

You could, of course, solve 3x+4y=11 for y to obtain the slope of the original line, and then substitute 8 for x and 0 for y into the point-slope formula for a straight line, or the slope-intercept formula.  The end result should be the same as above:  3x+4y=24

both of the questions?