Find θ between 90 and 360 degrees such that sinθ = sin 73

The scale factor applied was 1/2

step 1

Find the area of the original parallelogram

A=bh

substtute the given values

step 2

Find the scale factor

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z > scale factor

x ---> area of the dilated parallelogram

y ---> area of the original paeallelogram

so

we have

substitute

simplify

therefore

The scale factor applied was 1/2