Find coordinates of y = 4x^2+ 40x+112

Step-by-step explanation:

y = 4x²+ 40x+112 (:4)

x²+ 10x+ 28.

28

1. |. 28

2. |. 14

4. |. 7

(x+4)(x+7)=0

x= -4. V. x= -7

Now fill in the x= -4 in y so you get the Y-coordinate and do the same for x= -7

Anseer should be like: 'The coordinates are (x, y) and (x, y)

∠1 = 130

∠3 = 130

∠2 = 50

Step-by-step explanation:

180 - 50 = 130

∠1 = ∠3 = 130 degrees

∠2 = 50 degrees