Mathematics: Find dy dx of y equals the secant of the square root of x.

Find dy dx of y equals the secant of the square

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1910153

11.03.2022

$\bf y=sec(\sqrt{x})\implies y=sec\left( x^{\frac{1}{2}} \right)\implies \cfrac{dy}{dx}=\stackrel{\textit{chain rule}}{sec\left( x^{\frac{1}{2}} \right)tan\left( x^{\frac{1}{2}} \right)\cdot \cfrac{1}{2}x^{-\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=sec\left( x^{\frac{1}{2}} \right)tan\left( x^{\frac{1}{2}} \right)\cdot \cfrac{1}{2x^{\frac{1}{2}}}\implies \cfrac{dy}{dx}=\cfrac{sec\left( \sqrt{x} \right)tan\left( \sqrt{x} \right)}{2\sqrt{x}}$

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Ответ:

abdominguez8077

02.02.2020

Mathematics

2 is the same as 4

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Find dy dx of y equals the secant of the square root of x.

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