Mathematics: Find f (x) for f(x) = cos^2(3x^3).

Find f (x) for f(x) = cos^2(3x^3). - id2338055387, gabischmid8101

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twinkle713derp

04.02.2022

$f(x) = \cos^2(3x^3)\\f'(x) = \frac{d}{dx}[\cos^2(3x^3)]\\= 2\cos(3x^3) \cdot \frac{d}{dx}[cos(3x^3)]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot \frac{d}{dx}[3x^3]\\= 2\cos(3x^3) \cdot (-\sin(3x^3)) \cdot 9x^2\\= -18x^2\cos(3x^3)\sin(3x^3)$

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Ответ:

aeshaalhemri

13.02.2023

Mathematics

one key difference is that in constructing a square, you have to construct a perpendicular bisector but when constructing a hexagon, you do not have to construct a perpendicular bisector. one similarity is that both constructions rely on the radius/diameter.

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Find f'(x) for f(x) = cos^2(3x^3).

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