Find h(2) if h(x) = -16x2 + 32x

0

Step-by-step explanation:

h(x) = -16x^2 + 32x

Let x= 2

h(2) = -16(2)^2 + 32(2)

     = -16(4) +64

      =0

y = 1/3x + 70/3

Step-by-step explanation:

2 points on the graph:

(20, 30) and (50, 40)

Slope:

m=(y2-y1)/(x2-x1)

m=(40 - 30)/(50 - 20)

m= 10/30

m= 1/3

Slope-intercept:

y - y1 = m(x - x1)

y - 30 = 1/3(x - 20)

y - 30 = 1/3x - 20/3

y = 1/3x + 70/3