kat9940
28.10.2020 •
Mathematics
Find mWYZ as well Find mACB please help with both. Thank you every much! Triangles, Need help, right now I’m does adding more stuff so it can stop saying 20 characters.
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Ответ:
m<WYZ = 23°
m<ACB = 87°
Step-by-step explanation:
Problem 1: Find WYZ
Given,
m<WVX = (3x - 7)°
m<VYZ = (16x - 3)°
∆WYZ ~ ∆WVX, therefore:
m<WYZ = m<WVX (corresponding angles of similar triangles are congruent)
m<WYZ = (3x - 7)° (substitution)
Create an equation to find the value of x.
m<WYZ + m<VYZ = 180° (linear pair)
(3x -7)° + (16x - 3)° = 180° (substitution)
Solve for x
3x - 7 + 16x - 3 = 180
Add like terms
19x - 10 = 180
Add 10 to both sides
19x - 10 + 10 = 180 + 10
19x = 190
Divide both sides by 19
19x/19 = 190/19
x = 10
m<WYZ = (3x - 7)
Substitute x = 10
m<WYZ = 3(10) - 7 = 30 - 7
m<WYZ = 23°
Problem 2: Find m<ACB
Given,
m<A = 62°
m<AED = (11x - 2)°
m<B = (6x + 13)°
∆ADE ~ ∆ACB, therefore:
m<AED = m<B (corresponding angles of similar ∆s are congruent)
(11x - 2)° = (6x + 13)°
Solve for x
11x - 2 = 6x + 13
Collect like terms
11x - 6x = 2 + 13
5x = 15
Divide both sides by 5
5x/5 = 15/5
x = 3
m<ACB + m<B + m<A = 180° (sum of ∆)
m<ACB + (6x + 13) + 62° = 180° (substitution)
Plug in the value of x and solve
m<ACB + (6(3) + 13) + 62° = 180°
m<ACB + (6(3) + 13) + 62° = 180°
m<ACB + (18 + 13) + 62° = 180°
m<ACB + 31° + 62° = 180°
m<ACB + 93° = 180°
Subtract 93 from both sides
m<ACB = 180° - 93°
m<ACB = 87°
Ответ:
1.12
Step-by-step explanation:divide 3 by 25 and you get 0.12 but the add by 1