Find perimeter of the rectangle pqrs formed by points of intersection of parabolas y=2x^2−12 and y=−3x^2+8 and their projections on the x-axis.

using a graphical tool------ >see attached drawing

points of intersection of parabolas are--------->point P and point Q
point P(-2,-4)     point Q(2,-4)

their projections on the x-axis. are---- > point R and point S
point R(-2,0)      point S(2,0)

the sides length of of the rectangle are
PQ=RS= 4
PR=QS=4
Perimeter=PQ+RS+PR+QS=16

the answer is 16

I believe it should be 5.3487 since 283% is converted into 2.83 and multiplied by 1.89.