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19nnash
30.01.2020 •
Mathematics
Find sin (a-b) if sin a = 4/5 with a between 90 and 180 and if cos b = 3/5 with b between 0 and 90
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Ответ:
sin(A-B) = 24/25
Step-by-step explanation:
The trig identity for the differnce of angles tells you ...
sin(A -B) = sin(A)cos(B) -sin(B)cos(A)
We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.
And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.
Then ...
sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25
The desired sine is 24/25.
Ответ:
i am trying but I need help a lot
Step-by-step explanation: