xaiverrodriguez
29.01.2020 •
Mathematics
Find the 10th term of the following geometric sequence: 2, 8, 32, 128.
a. 248,221
b. 621,325
c. 164,357
d. 524,288
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Ответ:
Ответ:
so the nth term = (first term)*CR^(n-1)
= 2*4^(n-1)
substituting n=10
2*4^(10-1)
= 2*4^9
= 524,288
ans is D
Ответ: