esid906
12.05.2021 •
Mathematics
Find the angle between the pair of vectors to the nearest tenth of a degree.
3i+2j, -6i+5j
A. 107.5°
OB. 173.8°
>
C. 113.0°
O D. 106.5°
>
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Ответ:
RectangleP = 2(l + w)A = lw
SquareP = 4sA = s2
TriangleP = a + b + cA = 1/2bh
TrapezoidP = a + b1 + c + b2A = 1/2h(b1 + b2)
Isosceles TrapezoidP = 2w + b1 + b2A = 1/2h(b1 + b2)
CircleC = πd = 2 π rA = π r2
Box SA = 2lw + 2lh + 2whV = lwh
Sphere SA = 4 π r2V = 4/3 π r3
Cylinder SA = 2 π r(r + h)V = π r2h