Find the arc length of the curve below on the given interval. y equals 2 x Superscript 3 divided by 2 on [0 comma 9 ]

d=54.93

Step-by-step explanation:

From exercise we have y=2x^{3/2} on interval [0,9]

We calculate the arc length of the curve  on the given interval.

We have the formula:

d=\int\limits^a_b {\sqrt{1+f'(x)^2}} \, dx

we get

f(x)=y=2x^{3/2}

f'(x)=y'=3x^{1/2}

d=\int\limits^9_0 {\sqrt{1+(3x^{1/2})²}\, dx

d=\int\limits^9_0 {\sqrt{1+9x}}\, dx

d=[\frac{2·(9x+1)^{3/2}}{27}]_0^9

d=\frac{2·(82^{3/2}-2)}{27}

d=54.93

We use the site geogebra.org to drawn a graph.

I think the area is 72 sorry if it is wrong I tried

Step-by-step explanation: