Find the area and perimeter of a polygon with

Ответ:

josebienka

31.01.2022

Mathematics

76 and 34

Step-by-step explanation:

See attached

As we see this is a polygon with sides of AB=BC=AE and CD=DE

Sides AB=BC=AE equal to 8Sides CD=DE = $\sqrt{3^2 + 4^2}$ = 5

Area is the sum of areas of a square ABCE with side 8 and a triangle CDE with base of 8 and height of 3:

Area = 8*8 + 1/2*8*3 = 64 + 12 = 76Perimeter = 8*3 + 5*2 = 24 + 10 = 34
Find the area and perimeter of a polygon with vertices located at A(-4,-8), B(4, -8), C(4, 0), D(0,

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Find the area and perimeter of a polygon with vertices located at A(-4,-8), B(4, -8), C(4, 0), D(0, 3), and E(-4,0). Area =

Perimeter =

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Find the area and perimeter of a polygon with vertices located at A(-4,-8), B(4, -8), C(4, 0), D(0, 3), and E(-4,0). Area = Perimeter =

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Find the area and perimeter of a polygon with vertices located at A(-4,-8), B(4, -8), C(4, 0), D(0, 3), and E(-4,0). Area =

Perimeter =