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jmolina57
07.10.2019 •
Mathematics
Find the area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13.
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Ответ:
The other side of each right triangle is such that tan 60° = Heigth / 2
Then height = 2*tan60°.
The area of the trapezoid is height * (base 1 + base 2)/2
Then area = 2*tan (60°) * (13+9)/2 = 38.11
Ответ:
60
Step-by-step explanation:
∑[i=1,5] 4i = 4·1 + 4·2 + 4·3 + 4·4 + 4·5
= 4 + 8 + 12 + 16 + 20
= 60