Mathematics: Find the area of a 9-inch by 6-inch rectangle with a 4-inch by 4-inch square removed from one corner. a 70 in.mc001-1.jpg b 38 in.mc001-3.jpg c 200 in.mc001-2.jpg d 46 in.mc001-4.jpg

10500Step-by-step explanation:...

Find the area of a 9-inch by 6-inch rectangle with

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16.01.2022

B. $38\ in^2$

Step-by-step explanation:

Area of a rectangle with dimension " l by w" is given by :-

$A_r=l\times w$

Area of square with dimension "a by a" is given by :_

A_s=(a)^2

Now Using (1), Area of rectangle with dimension 9-inch by 6-inch will be :-

$A_r=9\times 9=54\ in^2$

Using (2), Area of square with dimension 4-inch by 4-inch will be :-

$A_s=4^2=16\ in^2$

Now, the required area = $A_r-A_s=54-16=38\ in^2$

Hence, B is the correct option.

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