Mathematics: Find the area of a sector with a central angle of 170° and a diameter of 9.1 cm. round to the nearest tenth.

Find the area of a sector with a central angle

Jaylen52709

03.01.2022

A central angle:
α = 170°
d = 9.1 cm
r = 9.1 : 2 = 4.55 cm
Area of a sector:
A = r² π α / 360°
A = ( 4.55 )² · 3.14 · 170° / 360°
A = 30.7 cm²

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shelbylowery789

03.01.2022

The area of sector is 30.7 cm².

Step-by-step explanation:

The diameter of a circle is 9.1 cm, so the radius of the circle is

$r=\frac{d}{2}=\frac{9.1}{2}=4.55$

The central angle of a sector is 170°.

The area of a sector is

$A=\pi r^2\times (\frac{\theta}{360})$

Where, r is radius and θ is central angle.

$A=\pi (4.55)^2\times (\frac{170}{360})$

A=30.712777

$A\approx 30.7$

Therefore the area of sector is 30.7 cm².

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gesteban

02.01.2021

I think 8 is B-9=x
9. 26.55-18.75=7.8/4=1.95
10. 202/2-30=P=71
11. -9.8
12. no idea
13. -6=x
14. 6=x
15. no idea
16. no idea
Thats all i Know sorry!

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