charlottiechecketts0
13.11.2020 •
Mathematics
Find the area of the circle.
Solved
Show answers
More tips
- S Sport Where can you play football in Moscow?...
- F Food and Cooking 10 Reasons Why You Should Avoid Giving Re-Gifts: An Informative Guide...
- S Sport How to wrap boxing hand wraps? Everything you need to know!...
- A Animals and plants 5 Tips for Taking Care of Yews to Keep Them Green and Beautiful...
- H Health and Medicine How to Calm Your Nerves? Expert Tips That Actually Work...
- O Other What is a Disk Emulsifier and How Does it Work?...
- S Sport How to Pump Your Chest Muscle? Secrets of Training...
- C Computers and Internet How to Get Rid of 3pic Infector: Everything You Need to Know...
- S Style and Beauty How to Grow Hair Faster: Real Methods and Advice...
- C Computers and Internet How to Top Up Your Skype Account Without Losing Money?...
Answers on questions: Mathematics
- M Mathematics Aconsultant has three sources of income—from teaching short courses, from selling computer software, and from advising on projects. his expected annual incomes from these...
- M Mathematics Whlch statement Is true about the slope of the graphed line?...
- M Mathematics Solve for s. 9|s+7| 9 write a compound inequality like 1 x 3 or like x 1 or x 3. use integers, proper fractions, or improper fractions in simplest form....
- S Social Studies How would you summarize or characterize lane dean jr. s conflicts, both internal and external?...
- H Health Nisha secured 73, 86, 78 and 75 marks in four tests. What is the least number of points she can secure in her next test if she is to have an average of 80?sind the...
Ответ:
50.24 centimeters squared
Step-by-step explanation:
The diameter (d) is 8 which means the radius is 4 (8/2)
we use the formula pi x radius^2
It says to use 3.14 for pi
so the equation is 3.14(4)^2=3.14 x 16 = 50.24
Ответ:
a) sin(2θ) = -√3/2
cos(2θ) = -1/2
tan(2θ) = √3
b) sin(2θ) = 4√5/9
cos(2θ) = 1/9
tan(2θ) = 4√5
Step-by-step explanation:
a) cos θ = -1/2
First, find sin θ using Pythagorean identity:
sin² θ + cos² θ = 1
sin² θ + (-1/2)² = 1
sin² θ + 1/4 = 1
sin² θ = 3/4
sin θ = ±√3/2
Since θ is in Quadrant II, sin θ > 0, so sin θ = +√3/2.
Now use double angle formulas to find each expression.
sin(2θ) = 2 sin θ cos θ
sin(2θ) = 2 (√3/2) (-1/2)
sin(2θ) = -√3/2
cos(2θ) = cos² θ − sin² θ
cos(2θ) = (-1/2)² − (√3/2)²
cos(2θ) = 1/4 − 3/4
cos(2θ) = -1/2
tan(2θ) = sin(2θ) / cos(2θ)
tan(2θ) = (-√3/2) / (-1/2)
tan(2θ) = √3
b) sin θ = -2/3
Repeat same steps as before.
First, find cos θ using Pythagorean identity:
sin² θ + cos² θ = 1
(-2/3)² + cos² θ = 1
4/9 + cos² θ = 1
cos² θ = 5/9
cos θ = ±√5/3
Since θ is in Quadrant III, cos θ < 0, so cos θ = -√5/3.
Now use double angle formulas to find each expression.
sin(2θ) = 2 sin θ cos θ
sin(2θ) = 2 (-2/3) (-√5/3)
sin(2θ) = 4√5/9
cos(2θ) = cos² θ − sin² θ
cos(2θ) = (-√5/3)² − (-2/3)²
cos(2θ) = 5/9 − 4/9
cos(2θ) = 1/9
tan(2θ) = sin(2θ) / cos(2θ)
tan(2θ) = (4√5/9) / (1/9)
tan(2θ) = 4√5