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jess2828
28.11.2019 •
Mathematics
Find the area of the surface of revolution generated by revolving the curve y = 3 sqrt (x), 0 < = x < = 4, about the x-axis.
okay, so i've set up the integral like this: 2pi ∫[0,4] (3 sqrt ((1+(1/ which is coming out to 108.5, but that's not giving me the right answer. can you me set up the integral correctly or tell me what i'm doing wrong?
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Ответ:
dA = 2πR*dS
where R is the distance between the centroid of the plane to the line of revolution.
I provided you an image how it's solved.
Mistakes:
R and the vertical strip there are shown. Distance from the centroid going to the line of revolution is simply half of the strip, that's why R = y/2
Your (y')² is not 1/4x, it should be 9/4x as being simplified. Just see on the image instead.
Ответ: