carnations
17.07.2019 •
Mathematics
Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0
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Ответ:
center is (4,-6)
radius=4
since
Ответ:
Substitute different values of x in y=3x and get corresponding y coordinates.
Substitute different values of x in y=3x and get corresponding y coordinates.Such as (0,0),(1,3),(2,6),(−1,−3),(−2,−6)
Substitute different values of x in y=3x and get corresponding y coordinates.Such as (0,0),(1,3),(2,6),(−1,−3),(−2,−6)Now, when x=−2 then y=−6 .