Mathematics: Find the coordinates of the vertex for the parabola defined by the given quadratic function f(x) = (x + 2)^2 + 2 a) (0,2) b) (2.0) c) (-2.2) d) (-2,-2) e) none

pointsStep-by-step explanation:...

Find the coordinates of the vertex for the parabola

Ответ:

alexandra2442

13.03.2022

Mathematics

(-2,2)

Step-by-step explanation:

Let's find the answer.

Because a tangent line for a parabola function is equal to 0 only at its vertex then:

$f(x)=(x+2)^{2}+2$

f'(x)=2*(x+2)

f'(x)=2x+4 so then:

f'(x)=0 when

0=2x+4

-2=x

For x=-2 f(x) is:

$f(x)=(x+2)^{2}+2$

$f(1)=(-2+2)^{2}+2$

f(x)=2

In conclusion, the vertex of the given parabola is (-2,2), so the answer is C. Although in your answer is reported as (-2.2) but I think was a typing mistake.

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Find the coordinates of the vertex for the parabola defined by the given quadratic function f(x) = (x + 2)^2 + 2 a) (0,2) b) (2.0) c) (-2.2) d) (-2,-2) e) none

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