Mathematics: Find the cube roots of 8(cos 216° + i sin 216°).

Find the cube roots of 8(cos 216° + i sin 216°).

Ответ:

stacykon

06.01.2022

$z^3=8(\cos216^\circ+i\sin216^\circ)$
$z^3=2^3(\cos(6^3)^\circ+i\sin(6^3)^\circ)$
$\implies z=8^{1/3}\left(\cos\left(\dfrac{216+360k}3\right)^\circ+i\sin\left(\dfrac{216+360k}3\right)^\circ\right)$

where k=0,1,2

. So the third roots are

$z=\begin{cases}2(\cos72^\circ+i\sin72^\circ)\\2(\cos192^\circ+i\sin192^\circ)\\2(\cos312^\circ+i\sin312^\circ)\end{cases}$

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Ответ:

WATBOI01

26.06.2020

Mathematics

student B is correct

Step-by-step explanation:

we know that 5 dollars will be donated for every 10 tickets sold. so we know that y is dollars donated so if we plug it in, we have 5 =_x . and we know that x represents tickets sold so 10 tickets are sold for 5 dollars donated so now we have 5 = _×10 and now we just fill in the blank, 1/2 times 10 equals 5 so student b is correct

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Find the cube roots of 8(cos 216° + i sin 216°).

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