sofo24
27.06.2020 •
Mathematics
Find the derivative of g(t)=3t^2+2t at t=-1 algebraically
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Ответ:
8.
Step-by-step explanation:
If y = ax^n then the derivative y' = anx^(n-1)
g(t) = 3t^2 + 2t so the derivative g'(t)
2*3 t^(2-1) + 2t(1-1)
= 6t + 2
At t =1 its value is 6 + 2 = 8.
Ответ: