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ashhuizing
03.07.2019 •
Mathematics
Find the distance from p to l. line l contains points (-4,2) and (3,-5). point p has coordinates (1,2). a. 55√5 , or appx 2.2 b. 67√7 , or appx 2.3 c. 52√2 , or appx 3.5 d. 103√3 , or appx 5.8
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Ответ:
To Find: Distance between point P to line l
Solution: Points lying on line l are suppose A (-4,2) and B (3,-5).
Equation of line passing through (p,q) and (a,b) is given by the equation
→![\frac{y-a}{x-b}=\frac{p-a}{q-b}](/tpl/images/0047/7401/604db.png)
Equation of line AB is ,
→![\frac{y-2}{x+4}=\frac{-5-2}{3+4}](/tpl/images/0047/7401/72513.png)
→y -2 = -1× (x +4)
→y -2 = -x -4
→x + y +4-2=0
→ x + y +2=0
Distance between point P (1,2) and line l whose equation is ,x+y+2=0 is given by=
=5√2/2=3.535(approx)→Option (C)
→Which is given by the formula ,i.e if a line has equation , Ax + By +c=0 and we have to find the distance from (p,q) is given by =![\frac{A p+ B q+ c}{\sqrt{A^{2}+B^{2}}}](/tpl/images/0047/7401/a8f07.png)
Ответ:
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Step-by-step explanation: