Mathematics: Find the distance from the point (6,-2) to the line y=2x-4.

Find the distance from the point (6,-2) to the

Ответ:

ptanner706

11.03.2022

Mathematics

The formula of a distance between a point (a, b)

and a line Ax + By + C = 0:

$d=\dfrac{|Aa+Bb+C|}{\sqrt{A^2+B^2}}$

We have the point (6, -2) → a = 6, b = -2

and the line y = 2x - 4 → 2x - y - 4 = 0 → A = 2, B = -1, C = -4.

Substitute:

$d=\dfrac{|(2)(6)+(-1)(-2)+(-4)|}{\sqrt{2^2+(-1)^2}}=\dfrac{|12+2-4|}{\sqrt{4+1}}=\dfrac{|10|}{\sqrt5}=\dfrac{10\sqrt5}{\sqrt5\cdot\sqrt5}\\\\=\dfrac{10\sqrt5}{5}=2\sqrt5$

d = 2√5

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Ответ:

pretti78

02.01.2021

Mathematics

2x =12

x = 12/2

x= 6

I hope I helped you‌^_^

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Find the distance from the point (6,-2) to the line y=2x-4.

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