Mathematics: Find the distance, midpoint, and slope of line AB. A(-2,-1) and B(6,3)

The temperature is 7 celsius and is also 56 fahrenheit....

Find the distance, midpoint, and slope of line AB.

awesome267

10.12.2021

$Slope (m) = \frac{y}{x}=\frac{1}{2} = 0.5$

$Distance (d) = \sqrt{x^2+y^2} =\sqrt{80} =8.9442719099992$

$Mindpoint =\left(2,\:1\right)$

Step-by-step explanation:

$Slope (m) = \frac{y}{x}=\frac{1}{2} = 0.5$

$0 = arctan(\frac{y}{x} = 26.565051177078^o$

$Distance (d) = \sqrt{x^2+y^2} =\sqrt{80} =8.9442719099992$

X = 6 – -2 = 8

Y = 3 – -1 = 4

Equation of the line:

y = 0.5x

When x=0, y = 0

When y=0, x = -0

Midpoint:

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$

$\left(x_1,\:y_1\right)=\left(-2,\:-1\right),\:\left(x_2,\:y_2\right)=\left(6,\:3\right)$

$=\left(\frac{6-2}{2},\:\frac{3-1}{2}\right)$

$=\left(2,\:1\right)$

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