Find the equation, in vertex form, for a parabola with a vertex of (2,-5) that goes through the point (3,4).

question 6 options:

y=.36(x+2)2−5

y=2(x−2)2−5

y=.75(x−2)2−5

y=9(x−2)2−5

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Y=9(x−2)²−5 is the solution

Explanation in full below

Using the vertex co-ordinates we can deduct the formula
y=a(x-2)²-5 

using the co-ordinate (3,4), use x=3, y=4 to find a

y=a(x-2)²-5 
4=a(3-2)² -5
4=a(1)²-5
4=a-5
a=9

Subsituting a into the first equation
y=a(x-2)²-5 
y=9(x-2)²-5 

The solution is y=9(x-2)²-5 

-9ab3a3b-52

Step-by-step explanation:

-8a3b+3a2b2-52+5a2b3a3b+7-9a2b2

-8a3b-6a-52+5a2b3a3b

-14a3b-52+5a2b3a3b

-9ab3a3b-52