Find the equation of a line through (1,1) which
isperpendicular to a line through (1,3) and (2,5).

Step-by-step explanation:

Point on a line is  (1,3) and (2,5).

slope of given line is 2

slope of perpendicular lines are negative reciprocal of one another

slope of perpendicular line is -1/2

slope = -1/2     (1,1)

add 1 on both sides

The answer:

1. ∠3, ∠5 are supplementary and ∠4, ∠6 are supplementary exterior sides in opposite rays.
2. ∠5 = ∠6 and ∠1 = ∠2 cpcte
3. ∠3 = ∠4 reflexive
4. mn = mn supplements to = angles.
5. triangle mnq congruent to triangle mnp asa 6. mq = mp given
the statements given above are true, but for proving   mq = mp, it is sufficient to prove that the triangle mqp is an isosceles.
for that 
∠1 = ∠2, because the line mn bisects ∠m in two similar parts, and 
besides pq and mn are  perpendicular, then it is obvious that mqp is an isosceles triangle.